POV-Ray : Newsgroups : povray.general : Problem with parameters : Re: Problem with parameters Server Time
31 Jul 2024 06:15:49 EDT (-0400)
  Re: Problem with parameters  
From: Tor Olav Kristensen
Date: 28 Feb 2008 21:33:23
Message: <47c76ef3@news.povray.org>
Warp wrote:
> Tor Olav Kristensen <tor### [at] toberemovedgmailcom> wrote:
>>> #macro TEST(A)
>>>    #local A = A + 1;
>>> #end
>>>
>>> #declare B = 1;
>>>
>>> TEST(B)
>> ...
> 
>> Your code above may work, but was it meant to work that way ?
>> I.e. Is the behaviour above a bug - or is it a feature ?
>> :)
> 
>> To me it is illogical that a #local statement should be
>> able to change _anything_ outside its scope.
> 
>   OTOH, how should it behave?
> 
>   Macro parameters are passed "by reference". This means that you can
> do this:
> 
> #macro TEST(A)
>   #declare A = A+1;
> #end
> 
> and it will modify the original identifier given as parameter.
> 
>   You want #local to not to modify the original identifier. So basically
> you want #local to make a local copy of the identifier and modify only that.
> But then all kinds of problematic situations may arise, for instance:
> 
> #macro TEST(A)
>   #local A = A+1;
>   #declare A = A+1;
> #end
> 
>   Should the #declare modify the local copy or the original identifier?
> 
>   More importantly: There are two A's now, the original and the local copy.
> Which 'A' should be used in the right-hand-side of the '=' of the #declare,
> the local copy or the original variable? If the #local only modifies a copy,
> then this "local A" will have a different value than the original identifier.

I see the problem.

(So if this is meant as a feature, it would be nice if the
documentation describes more in detail what effect #local has
on macro parameters.)

Maybe a solution could be to have only one assignment
directive (e.g. #set or #let or none) and let call-by-value
be the default for parameters to macros. call-by-reference
could be indicated by e.g. "var" in the macro declaration.

   #macro TEST(A, var B)
     #set A = A + 1;
     #set B = B + A;
   #end

   #set C = 1;
   #set D = 3;

   TEST(C, D)
   // C is still 1. D has been changed to 5.

Another possibility could be to use "in", "out" and "in out"
in front of the parameters, like in Ada.

http://www.csc.liv.ac.uk/~grant/Teaching/COMP205/paramPassing.html

-- 
Tor Olav
http://subcube.com


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