> So what's the difference? Well, let's try this:
> 
>   function solve2(a, b, c)
>   {
>     var det  = Math.sqrt(det2);
>     var det2 = b*b - 4*a*c;
>     var a2   = 2*a;
>     return Array((0-b-dat)/a2, (0-b+det)/a2));
>   }
> 
> Hmm, that's not going to work properly... However, the corresponding 
> Haskell works exactly as before:
> 
>   solve2 a b c =
>     let det  = sqrt det2
>         det2 = b*b - 4*a*c
>         a2   = 2*a
>     in  [(0-b-det)/a2, (0-b+det)/a2]
> 
> So in Haskell, the ordering doesn't matter.

http://rinkworks.com/stupid/cs_programming.shtml

"An introductory programming student once asked me to look at his 
program and figure out why it was always churning out zeroes as the 
result of a simple computation. I looked at the program, and it was 
pretty obvious:

begin
     readln("Number of Apples", apples);
     readln("Number of Carrots", carrots);
     readln("Price for 1 Apple", a_price);
     readln("Price for 1 Carrot", c_price);
     writeln("Total for Apples", a_total);
     writeln("Total for Carrots", c_total);
     writeln("Total", total);
     total := a_total + c_total;
     a_total := apples * a_price;
     c_total := carrots + c_price;
end;

  * Me: "Well, your program can't print correct results before they're 
computed."
  * Him: "Huh? It's logical what the right solution is, and the computer 
should reorder the instructions the right way."

---

So he was right after all...

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