"stbenge" <stb### [at] hotmailcom> wrote in message 
news:4786b44a@news.povray.org...
> [GDS|Entropy] wrote:
>> Yeah...
>
> CrapGadget... classic :)

Thanks, I borrowed that from Engadget (kinda like Techcrunch), it just 
seemed so fitting. ;-)

>> Trying to get used to array storage/retrieval in POV again, screwing 
>> around..not quite sure where I am going with this.
>>
>> Essentially I am mucking around with arrays of vectors which connect end 
>> to end. I am slowly integrating randomness and branch/object property 
>> variation.
>>
>> So I guess this could end up being either some kind of pulsing hydraulic 
>> atrocity when animated, or some sort of shrubbery when used with splines, 
>> and possibly some mutated horrific retrovirus when used with 
>> sphere_sweeps.
>>
>> I really don't know...or care for that matter, it just looks cool. ;-p
>> But I would appreciate any code example using adaptive multi-dimensional 
>> arrays. See below: [this is not the pov code which produced the image, 
>> this is just a flowing thought which attempts to clairify my goal] (keep 
>> in mind I've been up for like 18hrs too, so..yeah..I've probably screwed 
>> up lots of places and need sleep)
>
> Perhaps Gilles Tran has some code suitable for helping you toward your 
> goal -> http://www.oyonale.com/

I will look into this. I have always been a fan of his work.

>> Essentially What I am looking for in the final function is the ability to 
>> say: "There are X number of objects type Z of diameter N, in a row, each 
>> requiring two non-intersecting vectors, and each object to has one vector 
>> in common with the object which follows it."
>>
>> Did I state this clearly, or should I go to bed for a while?? ;-)
>
> Maybe, and probably. Is it possible to label the objects as you put them 
> into the array? Maybe another array can be used as a reference?

Hmm...I think I know what you mean, and I can imagine ways to numerically 
link the arrays, but as far as your exact meaning of a label, not so much.
Perhaps some small example?

> Sam

Thanks, Ian

Post a reply to this message