SharkD <nomail@nomail> wrote:
> #local increment = 1/radii;

  That's not an integer.

>  #local i = i + increment;

  And thus your loop counter isn't either.

> If "increment" is indeed stored as a float, shouldn't "6 * increment" evaluate
> to the same number as "increment + increment + increment + increment +
> increment + increment"?

  No. We are talking about floating point numbers with limited number of bits.
That kind of thing is *not* guaranteed at all.

-- 
                                                          - Warp

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