Tim Attwood escribió:
>> (1/sqrt(5) * ( (phi^(n+3)-1)/(phi-1) - ((1-phi)^(n+3)-1)/(1-phi-1) )
> P(n,k) = P(n-1,k-1)+P(n-k,k)
> P(n) ~ (1/(4*n*(sqrt 3))) * (e^(pi*(sqrt (2*n/3))))


O_o

Maybe I should stay away from the complex problems then.

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