Grassblade <nomail@nomail> wrote:
> That looks suspiciously like square root of 3. I don't know if trigonometry
> applies to image_width, but that would be the tan of 60 degrees. I have no
> clue why it would be so.

  If I'm not mistaken, the default 'angle' is 60 (or something close to it),
which is actually calculated from the default 'distance' and other defaults
affecting this value, and the size of the orthographic plane of projection
is calculated from these.

-- 
                                                          - Warp

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