Among other things, Lutz-Peter Hooge wrote:

>> Kinetic energy: 1/2 * m * v^2
>> Potential energy: g * m * h
> 
> This is the correct solution for a sliding (or slipping?
> what is the correct term?) particle, but not for a rolling ball.

It's a quick "ad-hoc" solution I wrote assuming no friction and no 
rotational energy :)

-- 
light_source{9+9*x,1}camera{orthographic look_at(1-y)/4angle 30location
9/4-z*4}light_source{-9*z,1}union{box{.9-z.1+x clipped_by{plane{2+y-4*x
0}}}box{z-y-.1.1+z}box{-.1.1+x}box{.1z-.1}pigment{rgb<.8.2,1>}}//Jellby

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