I'm sorry that this explanation is likely over my head and possibly not
exactly applicable to my situation. At least one problem is in the
difficulty of finding even a THIRD point without some stepwise creeping
along Val.
"Peter Popov" <peter [at] vip bg> wrote in message
news:l3j2pu02gocibkq3jkd9ngrtef5q4fu27o@4ax.com...
> You can fit them on the splines with a matrix, assuming that not only
> the distance between the splines is constant, but the vector itself
> (i.e. if you get rid of the vlength() in your definition, it should
> still yield a constant value)
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