POV-Ray : Newsgroups : povray.general : I have a.... : Re: I have a.... Server Time
6 Aug 2024 02:19:41 EDT (-0400)
  Re: I have a....  
From: N Shomber
Date: 24 Jun 2002 11:29:03
Message: <3d173abf$1@news.povray.org>
> if I remember right, tan()/sin() is cos()...

I believe:

sin()=opposite/hypotenuse
cos()=adjacent/hypotenuse
tan()=opposite/adjacent
csc()=hypotenuse/opposite
sec()=hypotenuse/adjacent
cot()=adjacent/opposite

and:
1/sin()=csc()
1/cos()=sec()
1/tan()=cot()
sin^2()+cos^2()=1
tan^2()+1=sec^2()
1+cot^2()=csc^2()

> if I remember right, tan()/sin() is cos()...

tan()=o/a
sin()=o/h
tan()/sin()=(o/a)/(o/h)
=(1/a)/(1/h)
=(h/a)
=sec()

Just a clarification.

N Shomber


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