oops...

> assume Lab=Lcb=L
> a) if 2*L<Lac then there is no solution
> b) if 2*L=Lac then there is one solution, the midway point between A and C
> (this is easy to figure out)
> c)  if 2*L>Lac, in 2D there are two solutions, in 3D the solution lies
> anywhere on a circle
>
> think of it as two circles (or spheres in 3D) of radius L at A and C, B is
> the intersecting point.
>
> -tgq
>
>

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