"Rune" <run### [at] mobilixnet dk> wrote in message
news:3cb81031$1@news.povray.org...
: I don't know how big to make the bounding objects.
For a Dodecahedron and Icosahedron I'd take a sphere { 0 1.2577 } and
for
a Octahedron a sphere { 0 1.73 }. The Tetrahedron is tricky.. a box?
Someone quick in math could calculate the difference of the volumes of
the shapes and the smallest box/sphere/whatever they fit in and see
thats the best result.
Ari-Matti
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