"Dave Dunn" wrote:
> If what you are saying is true, the initial value
> for scale on any given object would be scale <0,0,0>.

Scale is an operation, not a property of the object. Thus there is no such
thing as an initial scale.

No matter what you say, y is and will always be defined as <0,1,0> and y*2
is thus <0,2,0>. That's how vector operations work. The vector operations
don't care what keyword is in front of them, they always work the same way.

Rune
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