Achill wrote:
> 
> [...]
> >
> >
> > So the vector sum of an arbitrary surface and a sphere at <0,0,0> with
> > radius 1 is the same as with any other sphere with the radius 1?  Sounds
> > strange.  Furthermore this means that this sum is not commutative.
> >
> 
> The sum of a set with any sphere of the same radius is the same, up to a
> translation. Moreover, the operation is commutative.

So the sum of a 

sphere { <1,0,0>, 0.1 }

and a

sphere { <0,0,2>, 0.1 }

would be a 

sphere { <0,0,0>, 0.2 }

???

Now that's a really strange idea for combining shapes...

Christoph

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