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=Bob= wrote:
>
> Hi Tor,
>
> Thanks for responding. How would I know
> how many steps (NrOfSteps) to use? Or am
> I missing something? What I'm trying to achieve
> is to decrease a value over a known length in
> an unkown number of steps.
E.g.:
If your known length is e.g. 3.14 meter
(i.e. the difference between StartValue
and EndValue equals 3.14) and you want to
decrease the X value for every millimetre,
then just use 3140 steps.
(3.14m = 3140mm)
> Thanks for your help!
You're welcome.
Tor Olav
> "Tor Olav Kristensen" <tor### [at] hotmail com> wrote in message
news:3C855736.7D202442@hotmail.com...
>
> [My post deleted]
>
> : Since you're asking in povray.general,
> : I'll answer with a POV script:
> :
> : #declare StartValue = 31;
> : #declare EndValue = 3;
> : #declare NrOfSteps = 10;
> :
> : #declare dValue = (EndValue - StartValue)/NrOfSteps;
> : #declare Step = 0;
> : #while (Step <= NrOfSteps)
> : #declare X = StartValue + Step*dValue;
> : #debug "\n"
> : #debug str(X, 0, -1)
> : #declare Step = Step + 1;
> : #end // while
> : #debug "\n"
> :
> : Tor Olav
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