"Greg M. Johnson" wrote:

> I want the coordinates for a truncated cube, in terms of triangles.

If you have a cube going from <-1,-1,-1> to <1,1,1> and you want to truncate
it so each of the original six faces becomes a regular octagon, then the
vertices would be at





(2^3+2^3+2^3=24 vertices)

--
David Fontaine  <dav### [at] faricynet>  ICQ 55354965
My raytracing gallery:  http://davidf.faricy.net/

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