I've done this in a simplistic manner before (inaccurately, in other words) by
just translating the object upward a specified amount, rotating more and more
from a parallel standing position, then moving back up again the same amount
minus some to compensate for the lower and lower "fall".  Then the rotation
about the axis done last.  Without any real math either, sad to say  :-)

Bob

"Dave Blandston" <gra### [at] earthlinknet> wrote in message
news:3939a4e2@news.povray.org...
| Great! So did I... :)

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