excellent!  Thanks Josh...  Pictures always help me - sometimes more than
words or equations (sp?).

Mike

"Josh English" <eng### [at] spiritonecom> wrote in message
news:38AD6E03.69711C87@spiritone.com...
> Yer wish is my command. I'll try to have one in p.b.i by this afternoon.
I'm
> going to be away this weekend at a family reunion... so if I don't make it
I'll
> get it on Monday
>
> Josh
>
> Mike Weber wrote:
>
> > How about a picture explaining all this???
> > "Nieminen Juha" <war### [at] sarakerttunencstutfi> wrote in message
> > news:38ad1899@news.povray.org...
> > >   Yes, the weighted average of the three vertex normals. The weight is
the
> > > inverse distance of the point from the vertex (ie. when the point is
> > exactly
> > > at the vertex, the weight for that normal is 1 and for the other two
it's
> > 0;
> > > when it's exactly in the middle of the triangle the weight for all
normals
> > > will be 1/3).
> > >
> > > --
> > >
main(i,_){for(_?--i,main(i+2,"FhhQHFIJD|FQTITFN]zRFHhhTBFHhhTBFysdB"[i]
> > > ):5;i&&_>1;printf("%s",_-70?_&1?"[]":" ":(_=0,"\n")),_/=2);} /*-
Warp -*/
>
> --
> Josh English
> eng### [at] spiritonecom
> "May your hopes, dreams, and plans not be destroyed by a few zeros."
>
>

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