Another method... if you can deal with a slight increase in parse time.  Take the code
you have and copy it so it appears twice in a
row.  Then take the first occurance and change it like this (I commented the "ADDED"
lines to show which ones they were):

#declare STEP=0.2;

#declare NumLights = 0;  // ADDED

#declare M=-1;
#while (M<=1)
    #declare N=-1;
    #while (N<=1)
        #declare O=-1;
        #while (O<=1)
            #declare NumLights  = NumLights + 1; // ADDED
            #declare O=O+STEP;
        #end
    #declare N=N+STEP;
    #end
#declare M=M+STEP;
#end

Then you can divide by NumLights.  Just make sure STEP is the same in both sets of
loops.

-Slime

Paul Vanukoff <van### [at] primenetcom> wrote in message
news:38761c1c@news.povray.org...
>
> I am working on a spherical light, so far it looks something like this:
>
> #declare STEP=0.2;
>
> #declare M=-1;
> #while (M<=1)
>     #declare N=-1;
>     #while (N<=1)
>         #declare O=-1;
>         #while (O<=1)
>
>             #if ( (M*M+N*N+O*O) <= 1 )
>                 light_source
>                 {
>                     < M, N, O> color White/DIVISOR
>                 }
>             #end
>         #declare O=O+STEP;
>         #end
>     #declare N=N+STEP;
>     #end
> #declare M=M+STEP;
> #end
>
> Only problem is, I don't know what to set DIVISOR to, in order for the
> overall brightness to equal that of a single light_source.  I know it has
> something to do with the volume of a sphere, and the value of STEP. Does
> anyone know what formula to use?
>
> --
> Paul Vanukoff
> van### [at] primenetcom
>
>
>
>

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