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On Thu, 16 Sep 1999 10:25:09 -0800, David Heys wrote:
>Anyone else who wants to pipe in, or add in other nifty time saving
>formula's (like I believe the circumference of a circle is supposed to be
>equal to pi*(r^2)), please do. :{)
There's the Cosine Theorem:
c=sqrt(a^2+b^2-2ab*cos(C))
for sides a and b and the angle between them C. If C is 90 degrees, its
cosine is zero and the formula simplifies to the Pythagorean Theorem.
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