> It doesn't.  It computes the value of a+b at the time the #declare is
> parsed and puts the result in the "variable."

As one would expect.

> I'd guess that it's something odd about the way division works with
> vectors.  Try multiplying by .5 instead of dividing by 2.  If that
> works, it's probably a bug that should be looked at.

It did not work. It still renders incorrectly.

--
Anthony L. Bennett
http://welcome.to/TonyB

Non nova, sed nove.

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