>Yes, but make sure your normals are of the same length and that they
>are pointing in the same direction relative to the surface. (Clockwise
>vs. counterclockwise triangles)


   1-----5
  /  \    /  \
 /    \ /     \
2---3----6
 \   /  \
  \ /     \
   4

Do you mean that, when calculating for example the normals of vertice 1,
taking the directed edge 1/3, I have to take 1/3 too instead of 3/1, when I
calculate the normals of vertice 1 ?!
And that I have to fix the directions of any edge once and for all before
proceeding further calculations?

I almost suspected that it would become a little more complicated ...

Thanks for your patience

Andreas
ger### [at] netcolognede

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