POV-Ray: Newsgroups: povray.general: Vertices of a Icosahedron: Re: Vertices of a Icosahedron

POV-Ray : Newsgroups : povray.general : Vertices of a Icosahedron : Re: Vertices of a Icosahedron		Server Time 16 Nov 2024 05:20:22 EST (-0500)

From: Ken
Date: 5 Oct 1998 18:35:46
Message: <36193B51.50517A49@pacbell.net>

Mick Hazelgrove wrote:

> Help
> How can I calculate the 3D positions of the vertices of an Icosahedron
> Thanks in advance
>
> Mick Hazelgrove

Will this work for you ?

  -- 20 triangular faces 12 vertices 30 edges
icosa1   0.0000000000E+00  0.0000000000E+00  3.8042260652E-01
icosa2   3.4026032334E-01  0.0000000000E+00  1.7013016167E-01
icosa3   1.0514622242E-01  3.2360679775E-01  1.7013016167E-01
icosa4  -2.7527638409E-01  2.0000000000E-01  1.7013016167E-01
icosa5  -2.7527638410E-01 -2.0000000000E-01  1.7013016167E-01
icosa6   1.0514622242E-01 -3.2360679775E-01  1.7013016167E-01
icosa7   2.7527638409E-01  2.0000000000E-01 -1.7013016167E-01
icosa8  -1.0514622242E-01  3.2360679775E-01 -1.7013016167E-01
icosa9  -3.4026032334E-01  1.2378598452E-12 -1.7013016167E-01
icosa10 -1.0514622243E-01 -3.2360679775E-01 -1.7013016167E-01
icosa11  2.7527638409E-01 -2.0000000000E-01 -1.7013016167E-01
icosa12  0.0000000000E+00  0.0000000000E+00 -3.8042260652E-01

EndPointList Name X Y Z

Ken Tyler

Post a reply to this message