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Le 30/07/2015 03:39, Bald Eagle a écrit :
>
> So, I would normally just puzzle this out myself, but it's 98 degrees here
> (Fahrenheit, not rotationally ;) ) and my gray matter is cooked.
>
> Anyway, concerning the "Western Wheel" problem:
> http://www.f-lohmueller.de/pov_tut/animate/anim13e.htm
>
> I have a gear that turns 7 times in 37 frames.
> (it drives a gear that turns once per 7 revolutions, I'm doing a quick "36"
> frames, and cyclic animation is on - so it's 37)
> It has 5 spokes, and 55 gear teeth.
>
37 frames, but 36 movements, before repetition ? or 37 distinct moves
(between frame n and n+1) and frame 38 is identical to frame 1 ?
I always get confused by that fence problem.
> I'm assuming I take 360 degrees, then divide by 55 teeth, and multiply by 7
> revolutions to get the total apparent movement of a tooth. Then divide by 37
> frames to find the "apparent movement" of a tooth between frames in degrees.
>
> The "Western Wheel limit" is half of the span between teeth per frame, so that
> would be (360/55)/2.
>
> If the first calculation is correct, then if it's less than the limit, I
> shouldn't get the undesired visual effect. Correct?
You mean the visual effect of the wheel moving backward when rolling
forward ?
I'm not sure my eyes wouldn't rather spot the spokes than the teeth.
You can also help my poor brain by having a spottable unique feature on
wheel (such as a valve or a big mark/hole), easier to track
>
> Could someone check my logic / math?
>
> Thanks :)
>
>
>
>
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