John VanSickle wrote:
> Mueen Nawaz wrote:
>
>> It turns out this set has "measure" 0. And any integral of a
>> function (the uniform distribution in this case) over a set of measure
>> zero is 0.
>
> I understand that the Dirac delta function,
>
> http://en.wikipedia.org/wiki/Dirac_delta_function
>
> is an exception to this.
Well, it's not exactly a function.
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anl
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