clipka <ano### [at] anonymousorg> wrote:
> Am 29.03.2016 um 14:42 schrieb Lsq:
> > Hi,about the following codes,I have some questions:
> >
> > camera {
> >    location <10.0, 20.0, -100.0>
> >    angle 65
> >    right x*image_width/image_height
> > }
> >
> > Question:The formula used is direction_length = 0.5 * right_length / tan(angle /
> > 2) where right_length is the length of the right vector. How can I get the right
> > vector in this case or there is a default right vector?
>
> In the above case, you have specified the "right" vector as
> <image_width/image_height,0,0> yourself (because x is a constant equal
> to <1,0,0>), so I fail to see what your question is.
>
> The default "right" vector is x*1.33 (_not_ exactly 4/3).
>
>
> > camera {
> >    location <10.0, 20.0, -100.0>
> >    angle 65
> >    right x*image_width/image_height
> >    look_at <10.0, 20.0, 0.0>
> > }
> >
> > Question:the help file says,"The look_at modifier changes both the up and right
> > vectors." And the direction_length calculation depends on the right vector.In
> > such a situation,how to compute the direction_length? And I think that the
> > direction vector is parallel to look_at vector,is it right?
>
> As look_at only rotates the up, right and direction vectors, but leaves
> their length unchanged, direction_length is also unaffected.
>
> As for the direction vector's orientation, it will be parallel to the
> look_at vector _minus_ the camera location (becasue "look_at" does not
> actually specify a direction but a point).

Thanks a lot! I got it.

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