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On 3/11/2009 1:37 PM, Orchid XP v8 wrote:
> Given the miniscule difference, I don't think that has much to do with
> it. (I am, however, baffled as to why there's an area difference at all...)
You're baffled as to why two different rectangles with different side
lengths but equivalent diagonals have different areas?
--
...Chambers
www.pacificwebguy.com
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>> Given the miniscule difference, I don't think that has much to do with
>> it. (I am, however, baffled as to why there's an area difference at
>> all...)
>
> You're baffled as to why two different rectangles with different side
> lengths but equivalent diagonals have different areas?
Yes. I was under the impression that the square of the diagonal was
equal to the sum of the squares of the sides, which _should_ mean that
as one side gets shorter, the other side gets longer by exactly the same
amount, holding the area constant.
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Invisible <voi### [at] dev null> wrote:
> >> Given the miniscule difference, I don't think that has much to do with
> >> it. (I am, however, baffled as to why there's an area difference at
> >> all...)
> >
> > You're baffled as to why two different rectangles with different side
> > lengths but equivalent diagonals have different areas?
> Yes. I was under the impression that the square of the diagonal was
> equal to the sum of the squares of the sides, which _should_ mean that
> as one side gets shorter, the other side gets longer by exactly the same
> amount, holding the area constant.
That would mean that if one of the sides had zero length, then the other
side would have the same length of the diagonal and the area would still
be the same. Which is obviously impossible.
You are confusing the sum of the squares of the side lengths with the
product of the side lengths. Obviously they are different things.
--
- Warp
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>>> You're baffled as to why two different rectangles with different side
>>> lengths but equivalent diagonals have different areas?
>
>> Yes. I was under the impression that the square of the diagonal was
>> equal to the sum of the squares of the sides, which _should_ mean that
>> as one side gets shorter, the other side gets longer by exactly the same
>> amount, holding the area constant.
>
> That would mean that if one of the sides had zero length, then the other
> side would have the same length of the diagonal and the area would still
> be the same. Which is obviously impossible.
>
> You are confusing the sum of the squares of the side lengths with the
> product of the side lengths. Obviously they are different things.
Yes. Obviously I am wrong, since the actual results do not match my
expectations. All I said was that I am surprised. ;-)
Ironically, I'm currently reading
http://www.apa.org/journals/features/psp7761121.pdf
I guess I'm too stupid to realise how stupid I am... :-/
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Invisible a écrit :
> Ironically, I'm currently reading
>
> http://www.apa.org/journals/features/psp7761121.pdf
>
> I guess I'm too stupid to realise how stupid I am... :-/
I'm not sure inflated self-assessment is your main problem right now ;-)
--
Vincent
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>> I guess I'm too stupid to realise how stupid I am... :-/
>
> I'm not sure inflated self-assessment is your main problem right now ;-)
Well, I don't know either. I have little to compare against. :-\
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I'm not personally authorized to make any kind of official
statement/commitment, but I will talk to the founder today; the board and
partners may be interested as well.
I will let you know.
ian
"Darren New" <dne### [at] sanrrcom> wrote in message
news:49b81d05@news.povray.org...
> [GDS|Entropy] wrote:
>> The only way I'm getting that one though is if funding for this biofuels
>> startup comes through.
>
> I'm involved with prizecapital.net if you are interested in that. Sort of
> like X-Prize for biofuel start-ups.
>
> --
> Darren New, San Diego CA, USA (PST)
> My fortune cookie said, "You will soon be
> unable to read this, even at arm's length."
>
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Invisible wrote:
> scott wrote:
...
>>> The part I can't figure out is... how is the monitor electrically
>>> connected to the metal beam on the underside of my desk? (The desk
>>> itself is wood. And the monitor housing is plastic.) So how the hell
>>> did the charge get into the LCD??
>>
>> Charge doesn't only go through conductors, one of the tests we do is
>> to apply a discharge to the plastic casing of the display and to the
>> front surface (which is definitely not a conductor), it makes its way
>> fine to the electronics :-)
>
> o_O
>
> I guess if you apply a few thousand volts to something, life finds a way...
"Lec 1 | MIT 8.02 Electricity and Magnetism, Spring 2002"
http://www.youtube.com/watch?v=3omwHv3Cmog&feature=PlayList&p=C2CEECFD938FD494&index=1
--
Tor Olav
http://subcube.com
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