Invisible wrote:
> Please reparse my sentence. I said it *does* assume referential 
> transparency yet does nothing to *enforce* or even *check* for it.

Actually, thinking on it more, I don't think it assumes referential 
transparency.

    X = nodes(),
    Y = nodes(),
    X = Y.

(where "nodes()" returns the list of running computers, basically)

I am not sure that's guaranteed not to fail out when it compares the two 
lists, nor would you want it to.

-- 
   Darren New / San Diego, CA, USA (PST)
     "That's pretty. Where's that?"
          "It's the Age of Channelwood."
     "We should go there on vacation some time."

Post a reply to this message