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TheMightyZog wrote:
> Thanks Warp, but
> rotate<(degrees(atan2(1,2))),0,0>
> or
> rotate<(atan2(1,2)),0,0>
> is not the same as
> rotate<30,0,0>
>
> - 'tis a real puzzle!
>
the tangent of 30 degrees is NOT 1/2
degrees(atan2(1,2))= 26.56 degrees
degrees(atan2(sqrt(3),1))= 30 degrees
*
* *
sqrt(3) *30 * 2
* *
*90 60*
**********
1
sin(30)=1/2 cos(60)=1/2
cos(30)=sqrt(3)/2 sin(60)=sqrt(3)/2
tan(30)=1/sqrt(3) tan(60)=sqrt(3)/1
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Apologies for the trouble you have all been put through by my 'senior
moment'
I see the silly mistake now
And thank you Alan and Tim for your alternative suggestions
Zog
"Leroy" <lrw### [at] joplin com> wrote in message
news:467### [at] joplincom...
> TheMightyZog wrote:
> > Thanks Warp, but
> > rotate<(degrees(atan2(1,2))),0,0>
> > or
> > rotate<(atan2(1,2)),0,0>
> > is not the same as
> > rotate<30,0,0>
> >
> > - 'tis a real puzzle!
> >
> the tangent of 30 degrees is NOT 1/2
> degrees(atan2(1,2))= 26.56 degrees
> degrees(atan2(sqrt(3),1))= 30 degrees
> *
> * *
> sqrt(3) *30 * 2
> * *
> *90 60*
> **********
> 1
> sin(30)=1/2 cos(60)=1/2
> cos(30)=sqrt(3)/2 sin(60)=sqrt(3)/2
> tan(30)=1/sqrt(3) tan(60)=sqrt(3)/1
>
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"TheMightyZog" <Chr### [at] HotPOPcom> wrote:
> Apologies for the trouble you have all been put through by my 'senior
> moment'
> I see the silly mistake now
> And thank you Alan and Tim for your alternative suggestions
> Zog
>
triangle to remind me. That might be one of the reasons I use a modeler.
Stephen
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news:web.46703502695d64ebff6e04e90@news.povray.org...
> I'm ashamed to have to ask this, but I just can not remember how to
> calculate an angle in degrees if I know the opposite and adjacent side of
a
> right-angled triangle.
>
> My only excuse is that I'm an OAP and school was just years ago and then
> radians were not taught!
>
> Help!
>
> Thanks
> Zog
>
>
degrees(atan2(A,B))
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