Hello,

I have datas to plot in <y,z> plane from 0..max(MaxY,MaxZ).
Image ratio is 1:1.

To see full image, camera position is <???, max/2, max/2>
and look at <0, max/2, max/2> ok.

But how to compute the x part of camera location ?



thanks

-- 
Kurtz le pirate
Compagnie de la Banquise

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Le 10/07/2016 à 17:14, kurtz le pirate a écrit :
>
> Hello,
>
> I have datas to plot in <y,z> plane from 0..max(MaxY,MaxZ).
> Image ratio is 1:1.
>
> To see full image, camera position is <???, max/2, max/2>
> and look at <0, max/2, max/2> ok.
>
> But how to compute the x part of camera location ?


Found :
	ceil((max*0.50)/tan(radians(cameraAngle*0.50)))




-- 
Kurtz le pirate
Compagnie de la Banquise

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On 07/10/2016 11:14 AM, kurtz le pirate wrote:
>
> Hello,
>
> I have datas to plot in <y,z> plane from 0..max(MaxY,MaxZ).
> Image ratio is 1:1.
>
> To see full image, camera position is <???, max/2, max/2>
> and look at <0, max/2, max/2> ok.
>
> But how to compute the x part of camera location ?
>

You could, I think, use the orthographic camera without the angle 
keyword. Just some offset +-x, a direction vector toward your "data"
and in your case, symmetric adjustment of the up and right vector 
magnitudes to encompass your data if need be.

Bill P.

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