POV-Ray : Newsgroups : povray.general : Math help Server Time
2 Nov 2024 13:18:54 EDT (-0400)
  Math help (Message 1 to 9 of 9)  
From: SharkD
Subject: Math help
Date: 6 Jun 2010 10:49:37
Message: <4c0bb581@news.povray.org>
How do I calculate the length of segment f in the following image given 
points A, B and E?

http://i421.photobucket.com/albums/pp292/SharkD2161/Support/Geogebra/what_is_length_f.png


-- 
http://isometricland.com


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From: StephenS
Subject: Re: Math help
Date: 6 Jun 2010 11:05:01
Message: <web.4c0bb91274d55e2679fa9d0e0@news.povray.org>
SharkD <pos### [at] gmailcom> wrote:
> How do I calculate the length of segment f in the following image given
> points A, B and E?
>
>
http://i421.photobucket.com/albums/pp292/SharkD2161/Support/Geogebra/what_is_length_f.png
>
>
> --
> http://isometricland.com

Pythagorean theorem, AE and AG are known, find EG.
f = AC - EG

Or so I think :-)

Stephen S


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From: SharkD
Subject: Re: Math help
Date: 6 Jun 2010 11:51:05
Message: <4c0bc3e9$1@news.povray.org>
On 6/6/2010 11:04 AM, StephenS wrote:
> SharkD<pos### [at] gmailcom>  wrote:
>> How do I calculate the length of segment f in the following image given
>> points A, B and E?
>>
>>
http://i421.photobucket.com/albums/pp292/SharkD2161/Support/Geogebra/what_is_length_f.png
>>
>>
>> --
>> http://isometricland.com
>
> Pythagorean theorem, AE and AG are known, find EG.
> f = AC - EG
>
> Or so I think :-)
>
> Stephen S
>
>

AG is not known however. Anyway I found a better alternative so I don't 
need a solution any more.

-- 
http://isometricland.com


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From: Thorsten Froehlich
Subject: Re: Math help
Date: 6 Jun 2010 11:59:49
Message: <4c0bc5f5$1@news.povray.org>
On 06.06.10 17:51, SharkD wrote:
>>> http://isometricland.com
>>
>> Pythagorean theorem, AE and AG are known, find EG.
>> f = AC - EG
>>
>> Or so I think :-)
>>
>> Stephen S
>
> AG is not known however.

You know its length.

	Thorsten


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From: Reactor
Subject: Re: Math help
Date: 6 Jun 2010 20:55:01
Message: <web.4c0c42a974d55e26f11876270@news.povray.org>
SharkD <pos### [at] gmailcom> wrote:
> AG is not known however. Anyway I found a better alternative so I don't
> need a solution any more.
>
> --
> http://isometricland.com


AG is the radius of the circle.

-Reactor


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From: Alain
Subject: Re: Math help
Date: 7 Jun 2010 14:37:30
Message: <4c0d3c6a@news.povray.org>
Le 2010-06-06 11:51, SharkD a écrit :
> On 6/6/2010 11:04 AM, StephenS wrote:
>> SharkD<pos### [at] gmailcom> wrote:
>>> How do I calculate the length of segment f in the following image given
>>> points A, B and E?
>>>
>>>
http://i421.photobucket.com/albums/pp292/SharkD2161/Support/Geogebra/what_is_length_f.png
>>>
>>>
>>>
>>> --
>>> http://isometricland.com
>>
>> Pythagorean theorem, AE and AG are known, find EG.
>> f = AC - EG
>>
>> Or so I think :-)
>>
>> Stephen S
>>
>>
>
> AG is not known however. Anyway I found a better alternative so I don't
> need a solution any more.
>
AG = AC = AB = radius.

Alain


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From: Le Forgeron
Subject: Re: Math help
Date: 8 Jun 2010 03:22:42
Message: <4c0defc2$1@news.povray.org>
Le 06/06/2010 16:49, SharkD a écrit :
> How do I calculate the length of segment f in the following image given
> points A, B and E?
> 
>
http://i421.photobucket.com/albums/pp292/SharkD2161/Support/Geogebra/what_is_length_f.png

What tools are you allowed to use ?

EG²+AE² = AG² = AB²

ergo EG² = 1.2² - 0.8² = 36/25 - 16/25 = 20/25
EG = sqrt(20)/5

FG + EG = FE = AC = AB = 1.2

FG = (6-2*sqrt(5))/5 = 2/5 * (3 - sqrt(5))




-- 
A good Manager will take you
through the forest, no mater what.
A Leader will take time to climb on a
Tree and say 'This is the wrong forest'.


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From: SharkD
Subject: Re: Math help
Date: 8 Jun 2010 12:03:42
Message: <4c0e69de$1@news.povray.org>
On 6/8/2010 3:22 AM, Le_Forgeron wrote:
> Le 06/06/2010 16:49, SharkD a écrit :
>> How do I calculate the length of segment f in the following image given
>> points A, B and E?
>>
>>
http://i421.photobucket.com/albums/pp292/SharkD2161/Support/Geogebra/what_is_length_f.png
>
> What tools are you allowed to use ?
>
> EG²+AE² = AG² = AB²
>
> ergo EG² = 1.2² - 0.8² = 36/25 - 16/25 = 20/25
> EG = sqrt(20)/5
>
> FG + EG = FE = AC = AB = 1.2
>
> FG = (6-2*sqrt(5))/5 = 2/5 * (3 - sqrt(5))
>
>
>
>

As I said, I chose an alternative (actually better) method, so I no 
longer need the help. Thanks though!


-- 
http://isometricland.com


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From: SharkD
Subject: Re: Math help
Date: 8 Jun 2010 12:14:17
Message: <4c0e6c59$1@news.povray.org>
On 6/6/2010 11:51 AM, SharkD wrote:
> AG is not known however. Anyway I found a better alternative so I don't
> need a solution any more.
>

Oops! I meant EG, sorry!

-- 
http://isometricland.com


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