Oh, yes, I have to reduce the portion of the image to 960x1800, like the
main image. Is it?



news:41698912@news.povray.org...

> 41695904$1@news.povray.org...
> >> I rendered the image like this +w6400 +h4800 +SR0.44 +ER0.64 +SC0.55
> >> +EC0.75 and in BMP format is very big, it's 87'9 Mb. Is it normal?
> >
> > 6400 x 4800 pixels (30 Mpix image)  x  3 bytes (24 bit image)  =
92160000
> > bytes
> > which corresponds to the 87.9 MB you have (the BMP header adds a few
more
> > bytes).
> >
> > I'd suggest you save your images using a lossless compression format
> > such as PNG or TIFF.  Just use the POV-Ray +FN flag (for PNG) while
> > rendering,
> > or convert the BMP to e.g. PNG using your favorite image editor.
>
> Note that I personally favour BMP for output. The main reason is that
images
> of this size take ages to save in PNG in the image editing program I'm
using
> (and in the other I tested), so working on large PNG files can be really
> painful. Saving and loading BMPs is extremely fast in comparison.
>
> Also, while partial BMP files seem to be fool-proof, partial PNG files can
> be a problem (my editor don't open them for instance), so I don't think
it's
> advisable to use PNG as an output format in this case (converting the BMP
to
> PNG after the render is advisable). Of course, these PNG-related issues
may
> not exist with the image editor Oleguer is using, so your mileage may
> vary...
>
> G.
>
> -- 
> **********************
> http://www.oyonale.com
> **********************
> - Graphic experiments
> - POV-Ray and Poser computer images
> - Posters
>
>

news: 4169a055@news.povray.org...
> I think the problem is I did the portion of the image very big, is it 
> right?

What is the size, in pixels, of the image you're trying to send?

G.


-- 
**********************
http://www.oyonale.com
**********************
- Graphic experiments
- POV-Ray and Poser computer images
- Posters

That's it: Size: 2877x957, Main Area: 0/0 to0/0   461 KB.

Best regards,
Oleguer





news:4169bcd5$1@news.povray.org...

> news: 4169a055@news.povray.org...
> > I think the problem is I did the portion of the image very big, is it
> > right?
>
> What is the size, in pixels, of the image you're trying to send?
>
> G.
>
>
> -- 
> **********************
> http://www.oyonale.com
> **********************
> - Graphic experiments
> - POV-Ray and Poser computer images
> - Posters
>
>

news: 416a2b4b$1@news.povray.org...
> That's it: Size: 2877x957, Main Area: 0/0 to0/0   461 KB.

Well, as you can see it's too big as you made a mistake while passing the 
partial render parameters. Remove parts of it until it fits in 1280 x 960 
(or 1280 x 957).

G.


-- 
**********************
http://www.oyonale.com
**********************
- Graphic experiments
- POV-Ray and Poser computer images
- Posters

In article <416a2cea@news.povray.org> , "Gilles Tran" 
<gitran_nospam_@wanadoo.fr> wrote:

>> That's it: Size: 2877x957, Main Area: 0/0 to0/0   461 KB.
>
> Well, as you can see it's too big as you made a mistake while passing the
> partial render parameters. Remove parts of it until it fits in 1280 x 960
> (or 1280 x 957).

Gilles, the message Oleguer is quoting is from the povcomp submission
website.  It has nothing to do with the size of the image, Oleguer simply
did not enter any coordinates for the detail view area.

    Thorsten

____________________________________________________
Thorsten Froehlich, Duisburg, Germany
e-mail: tho### [at] trfde

Visit POV-Ray on the web: http://mac.povray.org

In article <416a2b4b$1@news.povray.org> , "Oleguer Vilella" 
<ole### [at] infonegociocom> wrote:

> That's it: Size: 2877x957, Main Area: 0/0 to0/0   461 KB.

On the detail image upload page you are asked to enter the pixel coordinates
of your detail image location within the main image. You have to enter valid
location values there. As it stands, you did not enter anything there at
all!

    Thorsten

____________________________________________________
Thorsten Froehlich, Duisburg, Germany
e-mail: tho### [at] trfde

Visit POV-Ray on the web: http://mac.povray.org

So I don't have to reduce the size. Ok, I understood that part. But how can
I now the cordinates?


news:416a3340@news.povray.org...
> In article <416a2b4b$1@news.povray.org> , "Oleguer Vilella"
> <ole### [at] infonegociocom> wrote:
>
> > That's it: Size: 2877x957, Main Area: 0/0 to0/0   461 KB.
>
> On the detail image upload page you are asked to enter the pixel
coordinates
> of your detail image location within the main image. You have to enter
valid
> location values there. As it stands, you did not enter anything there at
> all!
>
>     Thorsten
>
> ____________________________________________________
> Thorsten Froehlich, Duisburg, Germany
> e-mail: tho### [at] trfde
>
> Visit POV-Ray on the web: http://mac.povray.org

In article <416a3998$1@news.povray.org> , "Oleguer Vilella" 
<ole### [at] infonegociocom> wrote:

> So I don't have to reduce the size. Ok, I understood that part. But how can
> I now the cordinates?

As I already told you, please read the description on the samples page at
<http://www.povcomp.com/samples/>.  It explains how to compute all
detail-image related numbers.  If you have problems understanding anything
particular on that page, please ask specific questions.  If you have
difficulty with the language, I would recommend to find a friend or relative
more fluent in English to assist you understanding the instructions and
explain them to you locally.  It is essential that you read and seriously
attempt to understand those instructions for anybody here to help you with
specific problems.

    Thorsten

____________________________________________________
Thorsten Froehlich, Duisburg, Germany
e-mail: tho### [at] trfde

Visit POV-Ray on the web: http://mac.povray.org

Yes, Ok I had read this web page. Now I used this code "+SR0.44 +ER0.61
+SC0.58 +EC0.75". The main picture is in 1280x960.
1280/25= 51'2 and 960/25= 38'4.
How can I now if my square is 51'2 width and 38'4 height? Because I supose
that if the square is biger than 51'1x38'4 I can't upload it.

"In the above example, detail #1 occupies the area 424,328 to 615,583 in the
960x1280 image. This equates to +SC0.441667, +EC0.640625, +SR0.25625 and
+ER0.455469. These values are simply arrived at by dividing the desired
column by the width (e.g. 424/960) or the row by the height (e.g. 328/1280).
These won't necessarily always equate to the exact pixel you want but it
will be close enough for the purposes of the submission."
424/960= 0.441667, so +SC0.441667.
328/1280= 0.25625, so +SR0.25625.
How do you know the other number that appear on the exemple? ( +EC0.640625
and +ER0.455469).

I suposse the coordinates are my code: 0.44, 0.61, 0.58, 0.75. Is it?

Thanks to all the people who are helpping me.

Best regards,
Oleguer







news:416a3dda@news.povray.org...
> In article <416a3998$1@news.povray.org> , "Oleguer Vilella"
> <ole### [at] infonegociocom> wrote:
>
> > So I don't have to reduce the size. Ok, I understood that part. But how
can
> > I now the cordinates?
>
> As I already told you, please read the description on the samples page at
> <http://www.povcomp.com/samples/>.  It explains how to compute all
> detail-image related numbers.  If you have problems understanding anything
> particular on that page, please ask specific questions.  If you have
> difficulty with the language, I would recommend to find a friend or
relative
> more fluent in English to assist you understanding the instructions and
> explain them to you locally.  It is essential that you read and seriously
> attempt to understand those instructions for anybody here to help you with
> specific problems.
>
>     Thorsten
>
> ____________________________________________________
> Thorsten Froehlich, Duisburg, Germany
> e-mail: tho### [at] trfde
>
> Visit POV-Ray on the web: http://mac.povray.org

In article <416a6ee1@news.povray.org> , "Oleguer Vilella" 
<ole### [at] infonegociocom> wrote:

> How do you know the other number that appear on the exemple? ( +EC0.640625
> and +ER0.455469).

By performing the same computation as for the start row and column.

> I suposse the coordinates are my code: 0.44, 0.61, 0.58, 0.75. Is it?

No, as the upload page clearly states, you have to provide the pixel
co-ordinates. The relative co-ordinates are obviously not pixel coordinates.
As you arrive at the relative co-ordinates by dividing the pixel
co-ordinates, you have to simply reverse this operation to compute the pixel
co-ordinates from the relative co-ordinates. For example 1280*0.44=563.

    Thorsten

____________________________________________________
Thorsten Froehlich, Duisburg, Germany
e-mail: tho### [at] trfde

Visit POV-Ray on the web: http://mac.povray.org