 |
|
|
|
|
|
| |
| |
|
|
|
|
| |
| |
|
|
"Greg M. Johnson" wrote:
> I want the coordinates for a truncated cube, in terms of triangles.
If you have a cube going from <-1,-1,-1> to <1,1,1> and you want to truncate
it so each of the original six faces becomes a regular octagon, then the
vertices would be at
(2^3+2^3+2^3=24 vertices)
--
David Fontaine <dav### [at] faricy net> ICQ 55354965
My raytracing gallery: http://davidf.faricy.net/
Post a reply to this message
|
|
| |
| |
|
|
|
|
| |
| |
|
|
"Bob H." wrote:
>
> "Tor Olav Kristensen" <tor### [at] hotmailcom> wrote in message
> news:39E0F73A.B0E029C8@hotmail.com...
> |
> | I'll look into it. Where can I find these
> | rock making includes ?
>
> I'm having no luck finding the rock includes or macros, sorry. One thing is
> John Van Sickles and it seems Chris Huff may have something too (not sure),
> and at the POV Objects Collection... Steve Pidgeon was another person that
> did one I know.
>
> Bob
If I'm not mistaken John has removed his rock include from his
website but he may have included it with his subdivision surface
suite - http://users.erols.com/vansickl/sss.htm which is in it's
own right a fun toy to play with.
Steve's site is at:
http://www.iro.umontreal.ca/~pigeon/pub/PovPage/RockGen/RockGen.html
See also:
http://www.rahul.net/endl/mallan/html/rocks.htm
http://www-personal.umich.edu/~mstock/pages/rocktools.html
--
Ken Tyler - 1400+ POV-Ray, Graphics, 3D Rendering, and Raytracing Links:
http://home.pacbell.net/tylereng/index.html http://www.povray.org/links/
Post a reply to this message
|
|
| |
| |
|
|
|
|
| |
| |
|
|
On Sun, 08 Oct 2000 23:14:04 -0700, Ken wrote...
> If I'm not mistaken John has removed his rock include from his
> website but he may have included it with his subdivision surface
> suite - http://users.erols.com/vansickl/sss.htm which is in it's
> own right a fun toy to play with.
I had a look at that URL, and it seems that the Surface Subdivision Suite
page has moved to /dev/null <grin>, as the URL you posted points to a new
page, which gives a 404...
John?
Bye for now,
Jamie.
Post a reply to this message
|
|
| |
| |
|
|
|
|
| |
| |
|
|
> Yesterday I did some more work on some CSG-macros of mine.
> They will "round off" any concave shape made with intersections
> of planes, like the upper left shape.
Any chance of you posting the macro code itself...
Rarius
Post a reply to this message
|
|
| |
| |
|
|
|
|
| |
| |
|
|
Thanks, but what I meant is this:
Take perfect cube. set each edge on a grinding wheel such that the normal of
the two faces on this edge make a 45 degree angle with the normal of the
grinding wheel. Do it for just a second or two.
David Fontaine wrote:
> "Greg M. Johnson" wrote:
>
> > I want the coordinates for a truncated cube, in terms of triangles.
>
> If you have a cube going from <-1,-1,-1> to <1,1,1> and you want to truncate
> it so each of the original six faces becomes a regular octagon, then the
> vertices would be at
>
>
> (2^3+2^3+2^3=24 vertices)
>
> --
> David Fontaine <dav### [at] faricynet> ICQ 55354965
> My raytracing gallery: http://davidf.faricy.net/
Post a reply to this message
|
|
| |
| |
|
|
|
|
| |
| |
|
|
On Mon, 09 Oct 2000 08:27:41 -0400, Greg M. Johnson wrote:
>Thanks, but what I meant is this:
>
>Take perfect cube. set each edge on a grinding wheel such that the normal of
>the two faces on this edge make a 45 degree angle with the normal of the
>grinding wheel. Do it for just a second or two.
So what you want is a cube with beveled edges. The size of the bevel is a
factor in finding the corners.
What used to be a square face will still be a square face, but it will be
moved inward on all sides by the size of the bevel. What used to be an edge
will now be a rectangular face; connect corresponding edges of the new square
faces to find the twelve new faces. What used to be a vertex will now be a
triangular face; connect corresponding corners of the new square faces to
find the eight new faces. The final object will have 26 faces, with a total
of 44 triangles.
--
Ron Parker http://www2.fwi.com/~parkerr/traces.html
My opinions. Mine. Not anyone else's.
Proudly not helping RIAA and SDMI steal my rights --
http://www.eff.org/Misc/EFF/Newsletters/EFFector/HTML/effect13.08.html
Post a reply to this message
|
|
| |
| |
|
|
|
|
| |
| |
|
|
Jamie Davison wrote:
> I had a look at that URL, and it seems that the Surface Subdivision Suite
> page has moved to /dev/null <grin>, as the URL you posted points to a new
> page, which gives a 404...
Hmmm.... I'll see if I can track it down.
--
Ken Tyler
Post a reply to this message
|
|
| |
| |
|
|
|
|
| |
| |
|
|
Ron Parker wrote:
> ...
> So what you want is a cube with beveled edges. The size of the bevel is a
> factor in finding the corners.
>
> What used to be a square face will still be a square face, but it will be
> moved inward on all sides by the size of the bevel. What used to be an edge
> will now be a rectangular face; connect corresponding edges of the new square
> faces to find the twelve new faces. What used to be a vertex will now be a
> triangular face; connect corresponding corners of the new square faces to
> find the eight new faces. The final object will have 26 faces, with a total
> of 44 triangles.
Are you sure about all this ? :)
See enclosed image.
To Greg:
When I've cleaned up the source code (that I believe
solves your problem), I'll post it.
Tor Olav
--
mailto:tor### [at] hotmailcom
http://www.crosswinds.net/~tok/tokrays.html
Post a reply to this message
Attachments:
Download 'truncatedcube03.jpg' (18 KB)
Preview of image 'truncatedcube03.jpg'
|
|
| |
| |
|
|
|
|
| |
| |
|
|
Philip Cowley wrote:
> > Yesterday I did some more work on some CSG-macros of mine.
> > They will "round off" any concave shape made with intersections
> > of planes, like the upper left shape.
>
> Any chance of you posting the macro code itself...
Yes I will. -But it needs some more work first.
Right now I'm too tired to do this work.
Tor Olav
--
mailto:tor### [at] hotmailcom
http://www.crosswinds.net/~tok/tokrays.html
Post a reply to this message
|
|
| |
| |
|
|
|
|
| |
| |
|
|
"Greg M. Johnson" wrote:
> Thanks, but what I meant is this:
>
> Take perfect cube. set each edge on a grinding wheel such that the normal of
> the two faces on this edge make a 45 degree angle with the normal of the
> grinding wheel. Do it for just a second or two.
Ah, that's bevelled, not truncated :) (Besides i think my data was wrong, it
should have been (2-sqrt(2)) for perfect octagon)
so you want a perfect octagon for the cross section? hmm...
24 vertices, 18 faces, 60 triangles
--
David Fontaine <dav### [at] faricynet> ICQ 55354965
My raytracing gallery: http://davidf.faricy.net/
Post a reply to this message
|
|
| |
| |
|
|
|
|
| |
