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I fully agree with Shay's analysis of there being a problem.
The solution I came up with for the first shortest code contest was to have
folks rank their favorite six entries. That way the 0 vs 20 scenario was
out.
Shay wrote:
>
> See the problem? Six of the Seven voters preferred entry1, but because
> of the "deviant" way in which voter7 ranked the images, entry1 is in
> third place. Here's the "scaled" version:
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Cool. I'm honored it's being put to use.
St. wrote:
>
> The next one will be 'RTC' - Ray-Tracing Competition. This will be
> set
> with a topic chosen by using the system that Greg Johnson came up with
> whereby old book titles are used as the topic, (see other posts).
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"Greg M. Johnson" <pte### [at] thecommononethatstartswithYcom> wrote:
> I fully agree with Shay's analysis of there being a problem.
>
> The solution I came up with for the first shortest code contest was to have
> folks rank their favorite six entries. That way the 0 vs 20 scenario was
> out.
>
>
Yeah, this method is so much cleaner --- and lets you concentrate on
commenting, rather than trying to wiggle the scores into a ranking you
like. I use a top five ranking on meetsoup.com, but it's the same concept.
(Actually, I wanted to go all out to instant runoffs, but that seemed a
little much)
-Sam
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stm31415 wrote:
> "Greg M. Johnson" <pte### [at] thecommononethatstartswithYcom> wrote:
>
>>I fully agree with Shay's analysis of there being a problem.
>>
>>The solution I came up with for the first shortest code contest was to have
>>folks rank their favorite six entries. That way the 0 vs 20 scenario was
>>out.
>>
>>
>
>
>
> Yeah, this method is so much cleaner --- and lets you concentrate on
> commenting, rather than trying to wiggle the scores into a ranking you
> like. I use a top five ranking on meetsoup.com, but it's the same concept.
> (Actually, I wanted to go all out to instant runoffs, but that seemed a
> little much)
Another possible voting mechanism is to put all of the anims in a binary
tree, like a sports tournament. Each voter gets their own tree,
populated randomly, and lacking their own entry if they're an entrant.
Then each voter goes through each pair, choosing one to advance to the
next level, until they've picked first, second, 3-4, 5-6-7-8, and so on.
Then count the number of wins that each entry gets from all voters.
Regards,
John
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thanks so much for useful info
[url=http://globolstaff.com/][color=#FFFFFF][u]website update[/u][/color][/url]
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thanks so much for useful info
[url=http://globolstaff.com/][color=#FFFFFF][u]website update[/u][/color][/url]
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